8085 OPCODE CHART PDF
Each instruction has a one-byte (8-bit) operation codes or opcode. With 8- bit binary opcode, a total of different operation codes can. Intel instruction set. x0, x1, x2, x3, x4, x5, x6, x7, x8, x9, xA, xB, xC, xD, xE, xF. 0x, NOP 1 4 , LXI B,d16 3 10 , STAX B 1 7 , INX B 1 6 –K 1 1 ADDRESSING MODES OF Shown in the following are the sizes of a 5CH This can be verified from the opcode chart given in the previous chapter.
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Assume data is in register C.
Intel Microprocessor Instructions – Hex codes and Mnemonics
Write a program to shift an eight bit data four bits right. Exchange the contents of memory locations Statement: MVI is 0x00xxx where xxx encodes one of 8 possible registers. Assume the least significant digit is stored at H. Post as a guest Name. Sign up using Email and Password. Opxode program 1 direct addressing instruction is used, whereas in program 2 indirect addressing instruction is used.
Instruction Set Manual: Opcodes
Subtract two 8-bit numbers Sample problem: I was in my foolishness, was desperately trying to separate the opcode into two parts sequentially! Two digit BCD number is stored in memory location H.
Subtract the contents of memory location H from the memory location H and place the result in memory location H. Add contents of two memory locations Statement: Pack the two unpacked BCD numbers stored in memory locations H and H and store result in memory location H.
Write a program to shift a 16 bit data, 1 bit right.
Subtract the bit number in memory locations H and H from the bit number in memory locations H and H. Add the bit number in memory locations H and H to the bit number in memory locations H and H.
My book says that it is a two byte instruction where the first byte is the opcode and the second is the operand. In program 2, bit addition instruction DAD is used.
Store 8-bit data in memory
How 80085 “3E” tell the microprocessor both the information? Store 8-bit data in memory Program 1: Store the result in memory locations H and H with the most significant byte in memory location H. The result of both programs will be the same. In Program 1, direct addressing instructions are used, whereas in Program 2, vhart addressing instructions are used. Exchange the contents of memory locations H and H. Add the contents of memory locations H and H and place the result in memory location H.
Encoding the target register inside the instruction bits is very common. Sign up or log in Sign up using Google. Email Required, but never shown.